It seems that doing maths for as long as I can remember didn’t make it stick in my mind so I’m having a little refresh as I go. I’m starting with some basic trig.

**– Pythagorus’ Theorum – Find the length of a third side on a Right angled Triangle.
**

Very simple. Say we have a right angled triangle with sides a, b and c – where c is the hypotenuse…

Crucially, a² + b² = c²

AKA the sum of the areas of the two squares on the legs (

aandb) equals the area of the square on the hypotenuse (c).

So how about this triangle?

5² + 9² = c²

25 + 81 = c²

c² = 106

Now square root 106…

c = ~10.30 (4sf) or √106 in surd form.